3.31 \(\int \frac {\text {csch}^3(c+d x)}{a+b \text {sech}^2(c+d x)} \, dx\)

Optimal. Leaf size=87 \[ -\frac {\sqrt {a} \sqrt {b} \tan ^{-1}\left (\frac {\sqrt {a} \cosh (c+d x)}{\sqrt {b}}\right )}{d (a+b)^2}+\frac {(a-b) \tanh ^{-1}(\cosh (c+d x))}{2 d (a+b)^2}-\frac {\coth (c+d x) \text {csch}(c+d x)}{2 d (a+b)} \]

[Out]

1/2*(a-b)*arctanh(cosh(d*x+c))/(a+b)^2/d-1/2*coth(d*x+c)*csch(d*x+c)/(a+b)/d-arctan(cosh(d*x+c)*a^(1/2)/b^(1/2
))*a^(1/2)*b^(1/2)/(a+b)^2/d

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Rubi [A]  time = 0.12, antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {4133, 471, 522, 206, 205} \[ -\frac {\sqrt {a} \sqrt {b} \tan ^{-1}\left (\frac {\sqrt {a} \cosh (c+d x)}{\sqrt {b}}\right )}{d (a+b)^2}+\frac {(a-b) \tanh ^{-1}(\cosh (c+d x))}{2 d (a+b)^2}-\frac {\coth (c+d x) \text {csch}(c+d x)}{2 d (a+b)} \]

Antiderivative was successfully verified.

[In]

Int[Csch[c + d*x]^3/(a + b*Sech[c + d*x]^2),x]

[Out]

-((Sqrt[a]*Sqrt[b]*ArcTan[(Sqrt[a]*Cosh[c + d*x])/Sqrt[b]])/((a + b)^2*d)) + ((a - b)*ArcTanh[Cosh[c + d*x]])/
(2*(a + b)^2*d) - (Coth[c + d*x]*Csch[c + d*x])/(2*(a + b)*d)

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 471

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(e^(n -
1)*(e*x)^(m - n + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q + 1))/(n*(b*c - a*d)*(p + 1)), x] - Dist[e^n/(n*(b*c -
 a*d)*(p + 1)), Int[(e*x)^(m - n)*(a + b*x^n)^(p + 1)*(c + d*x^n)^q*Simp[c*(m - n + 1) + d*(m + n*(p + q + 1)
+ 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, q}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0] && LtQ[p, -1] && GeQ[n
, m - n + 1] && GtQ[m - n + 1, 0] && IntBinomialQ[a, b, c, d, e, m, n, p, q, x]

Rule 522

Int[((e_) + (f_.)*(x_)^(n_))/(((a_) + (b_.)*(x_)^(n_))*((c_) + (d_.)*(x_)^(n_))), x_Symbol] :> Dist[(b*e - a*f
)/(b*c - a*d), Int[1/(a + b*x^n), x], x] - Dist[(d*e - c*f)/(b*c - a*d), Int[1/(c + d*x^n), x], x] /; FreeQ[{a
, b, c, d, e, f, n}, x]

Rule 4133

Int[((a_) + (b_.)*sec[(e_.) + (f_.)*(x_)]^(n_))^(p_.)*sin[(e_.) + (f_.)*(x_)]^(m_.), x_Symbol] :> With[{ff = F
reeFactors[Cos[e + f*x], x]}, -Dist[ff/f, Subst[Int[((1 - ff^2*x^2)^((m - 1)/2)*(b + a*(ff*x)^n)^p)/(ff*x)^(n*
p), x], x, Cos[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f}, x] && IntegerQ[(m - 1)/2] && IntegerQ[n] && IntegerQ[p
]

Rubi steps

\begin {align*} \int \frac {\text {csch}^3(c+d x)}{a+b \text {sech}^2(c+d x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {x^2}{\left (1-x^2\right )^2 \left (b+a x^2\right )} \, dx,x,\cosh (c+d x)\right )}{d}\\ &=-\frac {\coth (c+d x) \text {csch}(c+d x)}{2 (a+b) d}-\frac {\operatorname {Subst}\left (\int \frac {b-a x^2}{\left (1-x^2\right ) \left (b+a x^2\right )} \, dx,x,\cosh (c+d x)\right )}{2 (a+b) d}\\ &=-\frac {\coth (c+d x) \text {csch}(c+d x)}{2 (a+b) d}+\frac {(a-b) \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\cosh (c+d x)\right )}{2 (a+b)^2 d}-\frac {(a b) \operatorname {Subst}\left (\int \frac {1}{b+a x^2} \, dx,x,\cosh (c+d x)\right )}{(a+b)^2 d}\\ &=-\frac {\sqrt {a} \sqrt {b} \tan ^{-1}\left (\frac {\sqrt {a} \cosh (c+d x)}{\sqrt {b}}\right )}{(a+b)^2 d}+\frac {(a-b) \tanh ^{-1}(\cosh (c+d x))}{2 (a+b)^2 d}-\frac {\coth (c+d x) \text {csch}(c+d x)}{2 (a+b) d}\\ \end {align*}

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Mathematica [C]  time = 2.05, size = 338, normalized size = 3.89 \[ -\frac {\text {sech}^2(c+d x) (a \cosh (2 (c+d x))+a+2 b) \left ((a+b) \text {csch}^2\left (\frac {1}{2} (c+d x)\right )+(a+b) \text {sech}^2\left (\frac {1}{2} (c+d x)\right )+8 \sqrt {a} \sqrt {b} \tan ^{-1}\left (\frac {\sinh (c) \tanh \left (\frac {d x}{2}\right ) \left (\sqrt {a}-i \sqrt {a+b} \sqrt {(\cosh (c)-\sinh (c))^2}\right )+\cosh (c) \left (\sqrt {a}-i \sqrt {a+b} \sqrt {(\cosh (c)-\sinh (c))^2} \tanh \left (\frac {d x}{2}\right )\right )}{\sqrt {b}}\right )+8 \sqrt {a} \sqrt {b} \tan ^{-1}\left (\frac {\sinh (c) \tanh \left (\frac {d x}{2}\right ) \left (\sqrt {a}+i \sqrt {a+b} \sqrt {(\cosh (c)-\sinh (c))^2}\right )+\cosh (c) \left (\sqrt {a}+i \sqrt {a+b} \sqrt {(\cosh (c)-\sinh (c))^2} \tanh \left (\frac {d x}{2}\right )\right )}{\sqrt {b}}\right )+4 a \log \left (\sinh \left (\frac {1}{2} (c+d x)\right )\right )-4 a \log \left (\cosh \left (\frac {1}{2} (c+d x)\right )\right )-4 b \log \left (\sinh \left (\frac {1}{2} (c+d x)\right )\right )+4 b \log \left (\cosh \left (\frac {1}{2} (c+d x)\right )\right )\right )}{16 d (a+b)^2 \left (a+b \text {sech}^2(c+d x)\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[Csch[c + d*x]^3/(a + b*Sech[c + d*x]^2),x]

[Out]

-1/16*((a + 2*b + a*Cosh[2*(c + d*x)])*(8*Sqrt[a]*Sqrt[b]*ArcTan[((Sqrt[a] - I*Sqrt[a + b]*Sqrt[(Cosh[c] - Sin
h[c])^2])*Sinh[c]*Tanh[(d*x)/2] + Cosh[c]*(Sqrt[a] - I*Sqrt[a + b]*Sqrt[(Cosh[c] - Sinh[c])^2]*Tanh[(d*x)/2]))
/Sqrt[b]] + 8*Sqrt[a]*Sqrt[b]*ArcTan[((Sqrt[a] + I*Sqrt[a + b]*Sqrt[(Cosh[c] - Sinh[c])^2])*Sinh[c]*Tanh[(d*x)
/2] + Cosh[c]*(Sqrt[a] + I*Sqrt[a + b]*Sqrt[(Cosh[c] - Sinh[c])^2]*Tanh[(d*x)/2]))/Sqrt[b]] + (a + b)*Csch[(c
+ d*x)/2]^2 - 4*a*Log[Cosh[(c + d*x)/2]] + 4*b*Log[Cosh[(c + d*x)/2]] + 4*a*Log[Sinh[(c + d*x)/2]] - 4*b*Log[S
inh[(c + d*x)/2]] + (a + b)*Sech[(c + d*x)/2]^2)*Sech[c + d*x]^2)/((a + b)^2*d*(a + b*Sech[c + d*x]^2))

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fricas [B]  time = 0.46, size = 1881, normalized size = 21.62 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(d*x+c)^3/(a+b*sech(d*x+c)^2),x, algorithm="fricas")

[Out]

[-1/2*(2*(a + b)*cosh(d*x + c)^3 + 6*(a + b)*cosh(d*x + c)*sinh(d*x + c)^2 + 2*(a + b)*sinh(d*x + c)^3 - (cosh
(d*x + c)^4 + 4*cosh(d*x + c)*sinh(d*x + c)^3 + sinh(d*x + c)^4 + 2*(3*cosh(d*x + c)^2 - 1)*sinh(d*x + c)^2 -
2*cosh(d*x + c)^2 + 4*(cosh(d*x + c)^3 - cosh(d*x + c))*sinh(d*x + c) + 1)*sqrt(-a*b)*log((a*cosh(d*x + c)^4 +
 4*a*cosh(d*x + c)*sinh(d*x + c)^3 + a*sinh(d*x + c)^4 + 2*(a - 2*b)*cosh(d*x + c)^2 + 2*(3*a*cosh(d*x + c)^2
+ a - 2*b)*sinh(d*x + c)^2 + 4*(a*cosh(d*x + c)^3 + (a - 2*b)*cosh(d*x + c))*sinh(d*x + c) - 4*(cosh(d*x + c)^
3 + 3*cosh(d*x + c)*sinh(d*x + c)^2 + sinh(d*x + c)^3 + (3*cosh(d*x + c)^2 + 1)*sinh(d*x + c) + cosh(d*x + c))
*sqrt(-a*b) + a)/(a*cosh(d*x + c)^4 + 4*a*cosh(d*x + c)*sinh(d*x + c)^3 + a*sinh(d*x + c)^4 + 2*(a + 2*b)*cosh
(d*x + c)^2 + 2*(3*a*cosh(d*x + c)^2 + a + 2*b)*sinh(d*x + c)^2 + 4*(a*cosh(d*x + c)^3 + (a + 2*b)*cosh(d*x +
c))*sinh(d*x + c) + a)) + 2*(a + b)*cosh(d*x + c) - ((a - b)*cosh(d*x + c)^4 + 4*(a - b)*cosh(d*x + c)*sinh(d*
x + c)^3 + (a - b)*sinh(d*x + c)^4 - 2*(a - b)*cosh(d*x + c)^2 + 2*(3*(a - b)*cosh(d*x + c)^2 - a + b)*sinh(d*
x + c)^2 + 4*((a - b)*cosh(d*x + c)^3 - (a - b)*cosh(d*x + c))*sinh(d*x + c) + a - b)*log(cosh(d*x + c) + sinh
(d*x + c) + 1) + ((a - b)*cosh(d*x + c)^4 + 4*(a - b)*cosh(d*x + c)*sinh(d*x + c)^3 + (a - b)*sinh(d*x + c)^4
- 2*(a - b)*cosh(d*x + c)^2 + 2*(3*(a - b)*cosh(d*x + c)^2 - a + b)*sinh(d*x + c)^2 + 4*((a - b)*cosh(d*x + c)
^3 - (a - b)*cosh(d*x + c))*sinh(d*x + c) + a - b)*log(cosh(d*x + c) + sinh(d*x + c) - 1) + 2*(3*(a + b)*cosh(
d*x + c)^2 + a + b)*sinh(d*x + c))/((a^2 + 2*a*b + b^2)*d*cosh(d*x + c)^4 + 4*(a^2 + 2*a*b + b^2)*d*cosh(d*x +
 c)*sinh(d*x + c)^3 + (a^2 + 2*a*b + b^2)*d*sinh(d*x + c)^4 - 2*(a^2 + 2*a*b + b^2)*d*cosh(d*x + c)^2 + 2*(3*(
a^2 + 2*a*b + b^2)*d*cosh(d*x + c)^2 - (a^2 + 2*a*b + b^2)*d)*sinh(d*x + c)^2 + (a^2 + 2*a*b + b^2)*d + 4*((a^
2 + 2*a*b + b^2)*d*cosh(d*x + c)^3 - (a^2 + 2*a*b + b^2)*d*cosh(d*x + c))*sinh(d*x + c)), -1/2*(2*(a + b)*cosh
(d*x + c)^3 + 6*(a + b)*cosh(d*x + c)*sinh(d*x + c)^2 + 2*(a + b)*sinh(d*x + c)^3 + 2*(cosh(d*x + c)^4 + 4*cos
h(d*x + c)*sinh(d*x + c)^3 + sinh(d*x + c)^4 + 2*(3*cosh(d*x + c)^2 - 1)*sinh(d*x + c)^2 - 2*cosh(d*x + c)^2 +
 4*(cosh(d*x + c)^3 - cosh(d*x + c))*sinh(d*x + c) + 1)*sqrt(a*b)*arctan(1/2*sqrt(a*b)*(cosh(d*x + c) + sinh(d
*x + c))/b) - 2*(cosh(d*x + c)^4 + 4*cosh(d*x + c)*sinh(d*x + c)^3 + sinh(d*x + c)^4 + 2*(3*cosh(d*x + c)^2 -
1)*sinh(d*x + c)^2 - 2*cosh(d*x + c)^2 + 4*(cosh(d*x + c)^3 - cosh(d*x + c))*sinh(d*x + c) + 1)*sqrt(a*b)*arct
an(1/2*(a*cosh(d*x + c)^3 + 3*a*cosh(d*x + c)*sinh(d*x + c)^2 + a*sinh(d*x + c)^3 + (a + 4*b)*cosh(d*x + c) +
(3*a*cosh(d*x + c)^2 + a + 4*b)*sinh(d*x + c))*sqrt(a*b)/(a*b)) + 2*(a + b)*cosh(d*x + c) - ((a - b)*cosh(d*x
+ c)^4 + 4*(a - b)*cosh(d*x + c)*sinh(d*x + c)^3 + (a - b)*sinh(d*x + c)^4 - 2*(a - b)*cosh(d*x + c)^2 + 2*(3*
(a - b)*cosh(d*x + c)^2 - a + b)*sinh(d*x + c)^2 + 4*((a - b)*cosh(d*x + c)^3 - (a - b)*cosh(d*x + c))*sinh(d*
x + c) + a - b)*log(cosh(d*x + c) + sinh(d*x + c) + 1) + ((a - b)*cosh(d*x + c)^4 + 4*(a - b)*cosh(d*x + c)*si
nh(d*x + c)^3 + (a - b)*sinh(d*x + c)^4 - 2*(a - b)*cosh(d*x + c)^2 + 2*(3*(a - b)*cosh(d*x + c)^2 - a + b)*si
nh(d*x + c)^2 + 4*((a - b)*cosh(d*x + c)^3 - (a - b)*cosh(d*x + c))*sinh(d*x + c) + a - b)*log(cosh(d*x + c) +
 sinh(d*x + c) - 1) + 2*(3*(a + b)*cosh(d*x + c)^2 + a + b)*sinh(d*x + c))/((a^2 + 2*a*b + b^2)*d*cosh(d*x + c
)^4 + 4*(a^2 + 2*a*b + b^2)*d*cosh(d*x + c)*sinh(d*x + c)^3 + (a^2 + 2*a*b + b^2)*d*sinh(d*x + c)^4 - 2*(a^2 +
 2*a*b + b^2)*d*cosh(d*x + c)^2 + 2*(3*(a^2 + 2*a*b + b^2)*d*cosh(d*x + c)^2 - (a^2 + 2*a*b + b^2)*d)*sinh(d*x
 + c)^2 + (a^2 + 2*a*b + b^2)*d + 4*((a^2 + 2*a*b + b^2)*d*cosh(d*x + c)^3 - (a^2 + 2*a*b + b^2)*d*cosh(d*x +
c))*sinh(d*x + c))]

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(d*x+c)^3/(a+b*sech(d*x+c)^2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Warn
ing, need to choose a branch for the root of a polynomial with parameters. This might be wrong.The choice was
done assuming [a,b]=[31,78]Warning, need to choose a branch for the root of a polynomial with parameters. This
 might be wrong.The choice was done assuming [a,b]=[-13,-93]Warning, need to choose a branch for the root of a
 polynomial with parameters. This might be wrong.The choice was done assuming [a,b]=[-65,-82]Warning, need to
choose a branch for the root of a polynomial with parameters. This might be wrong.The choice was done assuming
 [a,b]=[97,-56]Undef/Unsigned Inf encountered in limitEvaluation time: 0.45Limit: Max order reached or unable
to make series expansion Error: Bad Argument Value

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maple [A]  time = 0.32, size = 134, normalized size = 1.54 \[ \frac {\tanh ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d \left (a +b \right )}-\frac {a b \arctan \left (\frac {2 \left (a +b \right ) \left (\tanh ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+2 a -2 b}{4 \sqrt {a b}}\right )}{d \left (a +b \right )^{2} \sqrt {a b}}-\frac {1}{8 d \left (a +b \right ) \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}-\frac {\ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a}{2 d \left (a +b \right )^{2}}+\frac {\ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b}{2 d \left (a +b \right )^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csch(d*x+c)^3/(a+b*sech(d*x+c)^2),x)

[Out]

1/8/d*tanh(1/2*d*x+1/2*c)^2/(a+b)-1/d*a*b/(a+b)^2/(a*b)^(1/2)*arctan(1/4*(2*(a+b)*tanh(1/2*d*x+1/2*c)^2+2*a-2*
b)/(a*b)^(1/2))-1/8/d/(a+b)/tanh(1/2*d*x+1/2*c)^2-1/2/d/(a+b)^2*ln(tanh(1/2*d*x+1/2*c))*a+1/2/d/(a+b)^2*ln(tan
h(1/2*d*x+1/2*c))*b

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {{\left (a - b\right )} \log \left ({\left (e^{\left (d x + c\right )} + 1\right )} e^{\left (-c\right )}\right )}{2 \, {\left (a^{2} d + 2 \, a b d + b^{2} d\right )}} - \frac {{\left (a - b\right )} \log \left ({\left (e^{\left (d x + c\right )} - 1\right )} e^{\left (-c\right )}\right )}{2 \, {\left (a^{2} d + 2 \, a b d + b^{2} d\right )}} - \frac {e^{\left (3 \, d x + 3 \, c\right )} + e^{\left (d x + c\right )}}{a d + b d + {\left (a d e^{\left (4 \, c\right )} + b d e^{\left (4 \, c\right )}\right )} e^{\left (4 \, d x\right )} - 2 \, {\left (a d e^{\left (2 \, c\right )} + b d e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )}} - 8 \, \int \frac {a b e^{\left (3 \, d x + 3 \, c\right )} - a b e^{\left (d x + c\right )}}{4 \, {\left (a^{3} + 2 \, a^{2} b + a b^{2} + {\left (a^{3} e^{\left (4 \, c\right )} + 2 \, a^{2} b e^{\left (4 \, c\right )} + a b^{2} e^{\left (4 \, c\right )}\right )} e^{\left (4 \, d x\right )} + 2 \, {\left (a^{3} e^{\left (2 \, c\right )} + 4 \, a^{2} b e^{\left (2 \, c\right )} + 5 \, a b^{2} e^{\left (2 \, c\right )} + 2 \, b^{3} e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )}\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(d*x+c)^3/(a+b*sech(d*x+c)^2),x, algorithm="maxima")

[Out]

1/2*(a - b)*log((e^(d*x + c) + 1)*e^(-c))/(a^2*d + 2*a*b*d + b^2*d) - 1/2*(a - b)*log((e^(d*x + c) - 1)*e^(-c)
)/(a^2*d + 2*a*b*d + b^2*d) - (e^(3*d*x + 3*c) + e^(d*x + c))/(a*d + b*d + (a*d*e^(4*c) + b*d*e^(4*c))*e^(4*d*
x) - 2*(a*d*e^(2*c) + b*d*e^(2*c))*e^(2*d*x)) - 8*integrate(1/4*(a*b*e^(3*d*x + 3*c) - a*b*e^(d*x + c))/(a^3 +
 2*a^2*b + a*b^2 + (a^3*e^(4*c) + 2*a^2*b*e^(4*c) + a*b^2*e^(4*c))*e^(4*d*x) + 2*(a^3*e^(2*c) + 4*a^2*b*e^(2*c
) + 5*a*b^2*e^(2*c) + 2*b^3*e^(2*c))*e^(2*d*x)), x)

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mupad [B]  time = 3.07, size = 1586, normalized size = 18.23 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(sinh(c + d*x)^3*(a + b/cosh(c + d*x)^2)),x)

[Out]

((a*b)^(1/2)*(2*atan(((exp(d*x)*exp(c)*((64*(2*b^5*d*(a*b)^(1/2) + 2*a*b^4*d*(a*b)^(1/2) + 2*a^4*b*d*(a*b)^(1/
2) + 2*a^3*b^2*d*(a*b)^(1/2)))/(a^4*(a + b)^3*(d^2*(a + b)^4)^(1/2)*(2*a*b + a^2 + b^2)*(a^4*d^2 + b^4*d^2 + 4
*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2)) + (32*(a*b^3*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 +
 6*a^2*b^2*d^2)^(1/2) + a^3*b*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) - a^2*b^2*
(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2)))/(a^3*d*(a*b)^(1/2)*(a + b)^5*(2*a*b +
a^2 + b^2)*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2))) + (32*exp(3*c)*exp(3*d*x)*(
a*b^3*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) + a^3*b*(a^4*d^2 + b^4*d^2 + 4*a*b
^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) - a^2*b^2*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b
^2*d^2)^(1/2)))/(a^3*d*(a*b)^(1/2)*(a + b)^5*(2*a*b + a^2 + b^2)*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^
2 + 6*a^2*b^2*d^2)^(1/2)))*(a^8*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) + 5*a^7*
b*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) + a^3*b^5*(a^4*d^2 + b^4*d^2 + 4*a*b^3
*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) + 5*a^4*b^4*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b
^2*d^2)^(1/2) + 10*a^5*b^3*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2) + 10*a^6*b^2*
(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2)))/(64*a^2*b - 64*a*b^2 + 64*b^3)) - 2*at
an((a*exp(d*x)*exp(c)*(d^2*(a + b)^4)^(1/2))/(2*d*(a*b)^(1/2)*(a + b)^2))))/(2*(a^4*d^2 + b^4*d^2 + 4*a*b^3*d^
2 + 4*a^3*b*d^2 + 6*a^2*b^2*d^2)^(1/2)) - exp(c + d*x)/((exp(2*c + 2*d*x) - 1)*(a*d + b*d)) - (atan((exp(d*x)*
exp(c)*(b^7*(- a^4*d^2 - b^4*d^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1/2) - 3*a*b^6*(- a^4*d^2 - b^4
*d^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1/2) + 5*a^2*b^5*(- a^4*d^2 - b^4*d^2 - 4*a*b^3*d^2 - 4*a^3
*b*d^2 - 6*a^2*b^2*d^2)^(1/2) - 5*a^3*b^4*(- a^4*d^2 - b^4*d^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1
/2) + 3*a^4*b^3*(- a^4*d^2 - b^4*d^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1/2) - a^5*b^2*(- a^4*d^2 -
 b^4*d^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1/2)))/(b^8*d*(a^2 - 2*a*b + b^2)^(1/2) + 2*a^3*b^5*d*(
a^2 - 2*a*b + b^2)^(1/2) + a^6*b^2*d*(a^2 - 2*a*b + b^2)^(1/2)))*(a^2 - 2*a*b + b^2)^(1/2))/(- a^4*d^2 - b^4*d
^2 - 4*a*b^3*d^2 - 4*a^3*b*d^2 - 6*a^2*b^2*d^2)^(1/2) - (2*exp(c + d*x))/((a*d + b*d)*(exp(4*c + 4*d*x) - 2*ex
p(2*c + 2*d*x) + 1))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {csch}^{3}{\left (c + d x \right )}}{a + b \operatorname {sech}^{2}{\left (c + d x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(d*x+c)**3/(a+b*sech(d*x+c)**2),x)

[Out]

Integral(csch(c + d*x)**3/(a + b*sech(c + d*x)**2), x)

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